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2x^2+14x=130
We move all terms to the left:
2x^2+14x-(130)=0
a = 2; b = 14; c = -130;
Δ = b2-4ac
Δ = 142-4·2·(-130)
Δ = 1236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1236}=\sqrt{4*309}=\sqrt{4}*\sqrt{309}=2\sqrt{309}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{309}}{2*2}=\frac{-14-2\sqrt{309}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{309}}{2*2}=\frac{-14+2\sqrt{309}}{4} $
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